7n^2+4n+7=7

Solution for 7n^2+4n+7=7 equation:

7n^2+4n+7=7

We move all terms to the left:

7n^2+4n+7-(7)=0

We add all the numbers together, and all the variables

7n^2+4n=0

a = 7; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·7·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*7}=\frac{-8}{14}
=-4/7
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*7}=\frac{0}{14}
=0
$